I’ve been doing the Weekly
Challenges. The
latest
involved various sorts of sorting. (Note that this closes today.)
Task 1: Sorted Matrix
You are given a n x n
matrix where n >= 2
.
Write a script to find 3rd smallest element in the sorted matrix.
Examples indicate that no deduplication is needed, so there will
always be a third-smallest element.
Clearly the approach is to flatten everything into a list, sort it,
and extract the third element. Flattening is one of those relatively
new features that languages do in very different ways (or, in some
cases, not at all – I confess I've never particularly missed it in
Perl). In Raku:
sub sortedmatrix(@matrix) {
my @n = @matrix[*;*];
return @n.sort({$^a <=> $^b})[2];
}
JavaScript:
var n = matrix.flat();
Python:
n = list(chain.from_iterable(matrix))
I'm father fond of the variable-free* PostScript:
/sortedmatrix {
[ exch
{
aload pop
} forall
] quicksort 2 get
} bind def
* well, almost, my quicksort
uses a lot of variables…
Task 2: Max Number
You are given a list of positive integers.
Write a script to concatenate the integers to form the highest possible value.
The naïve approach would be to try all possible orderings. Obviously
that would get expensive very quickly.
In most situations one can simply stringify each number, reverse-sort
in string order, and concatenate the results (because the highest
numbers should always be in the leftmost positions in the output).
This looks pretty easy, but there's a fiddly edge case (which is why
example 5 exists): when two strings aren't of equal length, problems
arise.
56
should appear before 5
(565 > 556).
55
can appear before or after 5
.
54
should appear after 5
(554 > 545).
My solution is to extend each string by its final character until all
strings are the same length - so the 5
above becomes 55
for
string-ordering purposes.
Then I have the problem of wanting to sort the modified strings and
use that order to reorder the original strings. I use something like a
Schwartzian
transform,
except that in most languages I sort a list of indices rather than a
composite variable.
Kotlin:
fun maxnumber(lst: List<Int>): Int {
po
is the input list, stringified.
val po = lst.map {it.toString()}
pl
is the maximum length of any of those strings.
val pl = po.map {it.length}.maxOrNull()!!
pm
will hold the extended strings.
var pm = ArrayList<String>()
for (so in po) {
var sm = so
If this one is shorter than the longest, extend it by its last character.
if (so.length < pl) {
val c = so.lastOrNull()!!
for (_i in 1 .. pl - so.length) {
sm += c
}
}
pm.add(sm)
}
Generate the list of indices.
var pi = ArrayList((0 .. pm.size - 1).toList())
Sort it based on the contents of pm
.
pi.sortByDescending {pm[it]}
Use it to read out po
in the right order.
var out = ""
for (st in pi) {
out += po[st]
}
And convert back to integer.
return out.toInt()
}
In PostScript I ended up extending my sorting
library to
support multiple ways of indicating a custom sort order: you can now
specify a comparator function, or a list of keys, or a function to
generate keys.
Full code on
github.
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